In days of yore, we would do this with base-10 logs. In your example we'd write $\log \sqrt[36]{12345} = (1/36)\log(12345) =(1/36)4.09149 = .11365$. Then we'd take the antilog (which means using the log table backwards) and get $10^{0.11365} = 1.29913.$ I think the old calculators would grind out Taylor series for $\log$ and $10^x$, and more modern ones had tables in memory and would just look up the values.