No; a consequence of the fundamental theorem of arithmetic is that if $p^k=q^\ell$ for some primes $p,q$ and natural numbers $k,\ell > 0$, then $p=q$ and $k=\ell$.
No; a consequence of the fundamental theorem of arithmetic is that if $p^k=q^\ell$ for some primes $p,q$ and natural numbers $k,\ell > 0$, then $p=q$ and $k=\ell$.