$$\sin a=\frac12=\sin\frac\pi6\implies a=n\pi+(-1)^n\frac\pi6$$ where $n$ is any integer
As "a belong to the first positive quadrant," $\displaystyle a=\frac\pi6$ (setting $n=0$)
$$\sin a=\frac12=\sin\frac\pi6\implies a=n\pi+(-1)^n\frac\pi6$$ where $n$ is any integer
As "a belong to the first positive quadrant," $\displaystyle a=\frac\pi6$ (setting $n=0$)