\begin{align} \frac d {dx} 10^x & = ( 10^x\cdot\text{constant}) \approx 10^x \cdot (2.3) \\\\[10pt] \frac d {dx} 2^x & = ( 2^x \cdot \text{constant}) \approx 2^x\cdot (0.693) \end{align} etc. It is easy to show that the derivative of an exponential function is a constant multiple of the same exponential function.
Only when the bas is $e$ is the "constant" equal to $1$.
The fact that $x\mapsto e^x$ is its own derivative accounts for its incessant appearance in the study of differential equations. It also accounts for the fact that the "constant" is the base-$e$ logarithm of the base of the epxonential function.
That's the beginning of the story; there's a lot more to it.
The fact that the "constant" is equal to $1$ only when the base is $e$ is analogous to the fact that in the identity $$ \frac d {dx} \sin x = (\text{constant}\cdot \cos x) $$ the "constant" is $1$ only when **radians** are used rather than some other unit.