Of course. Take $A$ nuclear, $B$ non-nuclear, and consider $A\oplus B$. With $I=0\oplus B$, you have $(A\oplus B)/I\simeq A$.
Of course. Take $A$ nuclear, $B$ non-nuclear, and consider $A\oplus B$. With $I=0\oplus B$, you have $(A\oplus B)/I\simeq A$.