Let D be the point on AB such that CD is the angle bisector of $\angle ACB$.
Let the perpendicular bisector of CD cut CA and CB at M and N.
CMDN is the **only** rhombus that meets the requirement can be constructed.
Let D be the point on AB such that CD is the angle bisector of $\angle ACB$.
Let the perpendicular bisector of CD cut CA and CB at M and N.
CMDN is the **only** rhombus that meets the requirement can be constructed.