You just need a combination of scoops, AND a choice of cone.
The number of ways in which you can do this in $\displaystyle \binom{31}{2}+31$, the number of ways to choose two scoops, times $3$, the number of ways to choose a cone.
You just need a combination of scoops, AND a choice of cone.
The number of ways in which you can do this in $\displaystyle \binom{31}{2}+31$, the number of ways to choose two scoops, times $3$, the number of ways to choose a cone.