$A$ and $B$ are true by arithmetic of limits:
sum of limits acts like you would expect as far it's not "$\infty-\infty$", and for B consider $|a_n/b_n|\le |1/b_n|$ starting at some $N$
$C$ is false, you could get for example limit $-\infty$: $a_n=-1/n$, $b_n=n$.
while: $b_n/a_n=-n^2\rightarrow -\infty $