Can someone help me on this probability question please? I'm quite comfortable with probability, but sometimes the wording of the questions REALLY throw me off. Given the following problem: > On a production line, $12\%$ of items are imperfect, and $25\%$ of these are rejected. Perfect items are never rejected. If $3$ items are selected at random, find the following probabilities: i. The first item is rejected. ii. No item is rejected. The part I'm stuck at is the _"$25\%$ are rejected"_ part. Is it: 1. $P(I\cap R) = 0.25$ or 2. $P(R\mid I) = 0.25$ Where $R$ is rejected and $I$ is imperfect. I'm not asking for a solution to the problem. I just need help with the wording of the question.

25% of the imperfect items are rejected. 25% of overall items are rejected makes no sense since it clearly states that perfect items are never rejected and you would necessarily reject some perfect items otherwise. $P(R|I)=0.25$

Remember that $P(A\cap B)\leq P(A)$

$0.25=P(I\cap R)\leq P(I)=0.12$ yields a contradiction.