Artificial intelligent assistant

Applications discrete math A racketeer is allowed to bring no more than 3 of the 7 lawyers representing him to a Senate hearing. How many choices does he have? This is what I have done but the correct answer is 64. I'm not sure how to get that answer. $ C(7,3)=\frac{7!}{3!4!}=35$

"No more than 3" means he doesn't have to bring _exactly_ 3 of his 7 lawyers: he can also bring only 0, 1 or 2 of them:. This gives you \begin{align} \text{number} &= \binom{7}{0} + \binom{7}{1} + \binom{7}{2} + \binom{7}{3}\\\ &= 1 + 7 + 21 + 35\\\ & = 64 \end{align}

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