The number of anagrams of the word INTERNET is $$\frac{8!}{2!\cdot 2! \cdot 2!}=5040$$ because there are 8 letters with 2 Ns, 2 Es and 2 Ts.
How many of them begin with a vowel?
Now the first letter can be chosen in $3$ ways and the remaining places can be filled in $(8-1)!$ ways. Hence, in the above fraction, we replace $8!$ with $3\cdot 7!$: $$\frac{3\cdot 7!}{2!\cdot 2! \cdot 2!}=1890.$$