Let me do it this way:
* The symmetric matrices are closed in all $p \times p$-matrices (obvious), hence they are Polish.
* The positive definite matrices are an open cone in the symmetric matrices, hence they are Polish as well (open subsets of a Polish space are Polish -- this is a bit easier to prove than the fact on $G_{\delta}$'s).
* Finally, since the functions $f_{i}:A \mapsto a_{ii}$ are continuous, their simultaneous pre-image of $1$ is closed in the positive definite matrices, hence the positive definite correlation matrices are Polish.
The positive semi-definite case is even simpler, as the conditions are all closed.
Finally, I can only recommend working through the first few sections of Kechris, as most of these arguments become rather simple once one gets used to them.