$A$ has 3 shares in a lottery containing 3 prizes and 5 blanks;$B$ has two shares in a lottery containing 2 prizes and 6 blanks $A$ has 3 shares in a lottery containing 3 prizes and 5 blanks;$B$ has two shares in a lottery containing 2 prizes and 6 blanks.Compare their chances of success. Probability of $A$ winning the lottery is $\frac{3}{8}$. Probability of $B$ winning the lottery is $\frac{2}{8}$. But these ''shares'',how can i use them in the solution.They are confusing me. How can i solve this question,i made unfruitful tries for this question. Thanks.

"Compare their chances of success" is very vague.

P(A gets k prizes) = $\binom{3}{k}\binom{5}{3-k}/\binom{8}{3}$, k = 0 to 3

P(B gets k prizes) = $\binom{2}{k}\binom{6}{2-k}/\binom{8}{2}$ , k = 0 to 2

Now compare them in whichever way you think the questioner wants !