Let us assume the event (random variable) of geyser erupting within 50 minutes follows an exponential distribution
In other words P(X<=50minutes)= $1-e^{-\lambda (50)}$ = 2/3
Find lamda from this, The lamda is somewhere around 0.021972.
Now find P(X<=20 minutes) = $1-e^{-\lambda * (20)}$ = 0.35561.
That will be your answer.
Alternate Slick Answer:
Divide the 50 minute interval into five 10-minute intervals. Let Q be the probability that the geyser does not erupt in each of the 10 minute intervals. Thus, $Q^5 = \frac{1}{3}$ and $Q \approx 0.8027$. For 20 minutes it is just $1−Q^2$ or 35.56%.
Thanks
Satish