What you have calculated is the average number of injuries over 80 years. If every year you have a probability of 0.0139 of getting injured, the average number of injuries you will sustain in 80 years is $80 \times 0.0139 = 1.112$. On the other hand, the probability of not getting injured at all in 80 years is the product of the probabilities of not getting injured in year 1, year 2, ..., year 80 (assuming that these events occur independently), which is $(1-0.0139)^{80}$.
I recommend reading up on the binomial distribution.