Call the initial amounts of money $h$ (for Henry) and $f$ (for Frank). We know that:
$$6f = 5h$$ $$h-(50\%)h = f - 68$$
In other words:
$$f = \frac{5}{6}h$$ $$\frac{1}{2}h = f - 68$$
Substituting the first expression in the second gives:
$$\frac{1}{2}h = \frac{5}{6}h - 68$$
which becomes
$$-\frac{1}{3}h = - 68$$
so
$$h = 204$$
and the amount he has left at the end is half of that, so 102$.