Right-angled triangle turned around height to make cone A right angled triangle, having base 6.3 m and height equal to 10 cm, is turned around the height. Find the volume of the cone thus formed. Also find the surface area. I can solve this question there is only one hinderance that I need to overcome. Please help me to sort this out. My query : When right angled triangle is turned around its height, the height of the cone= height of the right angled triangle. **the base of the cone=?** slant height= hypotenuse of the right angled triangle.

The base of the cone is a circle with radius equal to the base of right triangle. To help you imagine better, you may first consider a square which is revolved around one of its sides. This will give a circular cylinder. Now, you can see why the base of the cone is a circle!