Suppose the planes from B, C, D, E, F, and G all land at A. Suppose the distance from A to B is 1. Then C must lie on the A-side of the perpendicular bisector of AB (in order to land at A instead of at B), and it must be outside the circle of radius 1 centered at B (so B lands at A, and not at C). Draw a picture and you'll be able to see that this forces the angle CAB to exceed 60 degrees.
More generally, if you stand at A and look at one of the airports and then turn until you face another airport, you must turn more than 60 degrees. But if you do this six times, you have turned over 360 degrees, which leads to a contradiction. So only five planes can land at A.