It is not vague. The image of your map (let us call it $\phi$) is, by definition, $\operatorname{Inn}G$. Therefore, $\operatorname{Inn}G\simeq G/\ker\phi$. Note that $\ker\phi$ is the center of $G$.
It is not vague. The image of your map (let us call it $\phi$) is, by definition, $\operatorname{Inn}G$. Therefore, $\operatorname{Inn}G\simeq G/\ker\phi$. Note that $\ker\phi$ is the center of $G$.