Total revenue during intervals The rate of flow of revenue is given by $$R'(t)=100t + 10e^{-t}$$ where $t$ is measured in years. Find the total revenue during the interval $$1 \le x \le 10$$ How can I calculate this because the revenue function is $$P(x) = R(x) - C(x)$$ and if I had the cost function, I would be able to determine the costs.

**Hint:** No, the total revenue function is $R(t)$. Thus the total revenue during the interval $1\leq t\leq 10$ is

$$R(t)=\int_1^{10} 100t + 10e^{-t} \; dt$$