Definitely not.
Look at a familiar case: let $\tau$ be the usual topology on $\Bbb R$, $\tau_1$ the indiscrete topology, and $\tau_2$ the discrete topology. In $\langle\Bbb R,\tau_1\rangle$ every sequence converges to every point; in $\langle\Bbb R,\tau_2\rangle$ the only convergent sequences are the eventually constant sequences, each of which converges to the point at which it is eventually constant. And in $\langle\Bbb R,\tau\rangle$ the sequence $\langle 2^{-n}:n\in\Bbb N\rangle$ is not constant converges only to $0$. The three topologies have three distinct families of convergent sequences.