You can impose the following model:
Save $P(0)$ in year 0, $P(1) = \alpha P(0)$ in year 1, $P(2) = \alpha P(1) = \alpha^2 P(0)$ in year 2, etc. for some $\alpha>1$. So you are geometrically/exponentially increasing the amount you save each year. After 10 years you will have $P(0) + P(1) + \; ... \; + P(10)$ = $P(0)[1+ \alpha + \alpha^2 + \; ... \; + \alpha^{10}] = P(0) \frac{\alpha^{10}-1}{\alpha-1}$.
Say $\alpha=1.5$. At the end you will have $113.33 P(0)$, which means $P(0) = 882.38$ if you want the final amount to be 100,000. With this model, you will have to save $\$882.38$ in year 0, $\$1323.60$ in year 1, ..., and $\$5088.2$ in year 10 (which is still reasonable).