Your inequalities are right. Now see here how to solve the a linear program graphically. Below the picture shows the graph of your problem.
> I got $Z_{min}$ min at two points (80,100) and (0, 700/3) the value of Zmin in both cases is 700 now how do we chose between them ?
As you see at the graph that after the shift the objective function lies direcly on the first constraint $y\geq \frac{700}3-\frac53\cdot x$. If we solve the objective function for y we get $y=\frac{z}3-\frac53\cdot x$
The reason why the objective function lies directly on the first constraint is that both have the same slope of $-\frac53$.
Thus the optimal solution is on every point on the constraint.
$(x^*,y^*)=\left(x, \frac{700}3-\frac53\cdot x\right)$, where $0\leq x\leq 80$
So both solutions you mentioned are valid. But all solutions in between them as well.
![enter image description here](