Your answer is correct. \begin{align*} x &= 15 \cos 130^\circ + 11 \cos 190^\circ \approx -20.4746994 \text{ knots} \\\ y &= 15 \sin 130^\circ + 11 \sin 190^\circ \approx 9.5805366 \text{ knots} \\\ r &= \sqrt{x^2 + y^2} \approx 22.6 \text{ knots} \\\ \theta &= 180^\circ + \arctan (y \; / \; x) \approx 154.9^\circ \end{align*}