**Hint:** You can buy $n$ bear claws, where $n \in N =\\{6a+9b+20c \,| a,b,c \in \Bbb{N}\\} $.
Let $M = \\{m|m \in \Bbb N \wedge m \
otin N\\}$.
You want $\sup M$.
Notice that if $b,c = 0$, every sixth number is in $N$. This implies that if six consecutive numbers are in $N$, all numbers greater than those will also be in $N$.